JSONP

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JSONP


JSONP is a method for sending JSON data without worrying about cross-domain issues.
JSONP does not use the XMLHttpRequest object.
JSONP uses the <script> tag instead.

JSONP Intro

JSONP stands for JSON with Padding.

Requesting a file from another domain can cause problems, due to cross-domain policy.
Requesting an external script from another domain does not have this problem.
JSONP uses this advantage, and request files using the script tag
instead of the XMLHttpRequest object.


<script src="demo_jsonp.php">

The Server File
The file on the server wraps the result inside a
function call:

Example

<?php$myJSON = '{ "name":"John", "age":30, "city":"New York" }';
echo "myFunc(".$myJSON.");";
?>
Show PHP file »

The result returns a call to a function named "myFunc" with the JSON data as
a parameter.
Make sure that the function exists on the client.
The JavaScript function
The function named "myFunc" is located on the client, and ready to handle
JSON data:

Example

function myFunc(myObj)
{  document.getElementById("demo").innerHTML =
myObj.name;
}
Try it Yourself »








Creating a Dynamic Script Tag
The example above will execute the "myFunc" function when the page is
loading, based on where you put the script tag, which is not very satisfying.
The script tag should only be created when needed:

Example
Create and insert the <script> tag when a button is clicked:

function clickButton() {  let s = document.createElement("script");  s.src = "demo_jsonp.php";  document.body.appendChild(s);
}
Try it Yourself »


Dynamic JSONP Result
The examples above are still very static.
Make the example dynamic by sending JSON to the php file, and let the php file return a JSON object based on
the information it gets.

PHP file

<?phpheader("Content-Type: application/json; charset=UTF-8");$obj =
json_decode($_GET["x"], false);
$conn = new mysqli("myServer", "myUser", "myPassword", "Northwind");
$result = $conn->query("SELECT name FROM
".$obj->$table." LIMIT ".$obj->$limit);$outp = array();
$outp = $result->fetch_all(MYSQLI_ASSOC);echo "myFunc(".json_encode($outp).")";?>

PHP File explained:

Convert the request into an object, using the PHP function
json_decode().
Access the database, and fill an array with the requested data.
Add the array to an object.
Convert the array into JSON using
the json_encode() function.
Wrap "myFunc()" around the return object.


JavaScript Example
The "myFunc" function will be called from the php file:

const obj = { table: "products", limit: 10 };
let s = document.createElement("script");
s.src = "jsonp_demo_db.php?x=" + JSON.stringify(obj);
document.body.appendChild(s);

function myFunc(myObj) {
  let txt = "";  for (let x in myObj)
{    txt += myObj[x].name + "<br>"; 
}  document.getElementById("demo").innerHTML = txt;}
Try it Yourself »


Callback Function
When you have no control over the server file, how do you get the server file
to call the correct function?
Sometimes the server file offers a callback function as
a parameter:

Example
The php file will call the function you pass as a callback parameter:

let s = document.createElement("script");
s.src = "jsonp_demo_db.php?callback=myDisplayFunction";
document.body.appendChild(s);

Try it Yourself »













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Reference: https://www.w3schools.com/js/js_json_jsonp.asp